College Alegebra
posted by Lost in Logarithms .
I know I have to take the log of both sides, but I don't seem to get how they work out!
Can anyone explain how to do
3e^(1+x) = 2
AND
10^(2x+3) = 280
If you walk me through one I should be able to figure out the other. Hopefully...
I think you need to go back to one of the log rules:
log[base A](A^n)=n
For example:
log[base10](10^3)=3
similarly
log[base e](e^x)=x
Does this help?
Honestly... no X_X. Don't you love college professors who don't /actually/ teach. Thanks for trying. I'm going to try and find someone who can show me.
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