Yancy wrote two novels that together contain 580 pages. His longer novel has 160 pages more than his shorter novel. How many pages are contained in Yancy's shorter novel?

How about:
let the number of pages in the shorter book be n
then the number of pages in the longer book must be n+160, ( they told us that)

"together" they contain 580 pages ....
n + n+160 = 580

etc

210

h√hsv˙as

To find the number of pages contained in Yancy's shorter novel, we can set up an equation using the information provided.

Let the number of pages in the shorter novel be n.
Then, the number of pages in the longer novel is n + 160, as stated in the question.

Together, the two novels contain 580 pages, so we can write the equation:
n + (n + 160) = 580

Simplifying the equation, we have:
2n + 160 = 580

Subtracting 160 from both sides of the equation:
2n = 420

Dividing both sides by 2:
n = 210

Therefore, Yancy's shorter novel contains 210 pages.

To find the number of pages in Yancy's shorter novel, let's assign a variable to represent the number of pages.

Let's assume the number of pages in the shorter novel is n.

According to the problem, Yancy's longer novel has 160 pages more than his shorter novel. So, the number of pages in the longer novel is n + 160.

Together, the two novels contain 580 pages. So, we can set up an equation:

n + (n + 160) = 580

Simplifying the equation:

2n + 160 = 580

Subtracting 160 from both sides:

2n = 420

Dividing both sides by 2:

n = 210

Therefore, Yancy's shorter novel contains 210 pages.