algebra 1 help

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One number is 6 more than another. If the sum of the smaller number and 3 times the larger number is 34, find the two numbers.

what am i suppose to do
i am reading as this but i know i am wrong

34=(x+6)+y*3

n + 3(n+6)=34

n is the smaller. the sum of the smaller and three times the larger is 34.
solve for n first.

• algebra 1 help -

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