A weight lifter returned from the grocery store and unpacked his purchases, fitting everything into the refrigerator door. If the dimensions of the door are 2 meters * 0.57 meters, and he applies a force of 77 N at an angle of 120 degrees with respect to the door, what is the magnitude of the torque created on the door’s hinge?
It depends upon where the force is applied and how the angle of the door (relative to which the force is applied) is defined.
Since this force is presumably used to put things in the door shelves, and not to open or close it, the force is aplied in many different locations. The question is confusingly written.
Well that's all the information they give me, and I typed it exactly word for word from the problem. Oh well I was totally lost and thought someone else might be able to figure it out! Thanks anyway!
In that case, we can approach the problem by calculating the torque based on the given information. Torque is a measure of the turning force around an axis and is calculated as the product of the force and the perpendicular distance from the axis of rotation to the line of action of the force.
To solve this problem, we need to use the formula for torque:
Torque = force * perpendicular distance
Since the force is given as 77 N and the angle is 120 degrees, we need to determine the perpendicular distance from the hinge to the line of action of the force. However, since the location where the force is applied is not specified, we cannot directly calculate the perpendicular distance.
If we assume that the force is applied at a specific point along the door, we can calculate the perpendicular distance for that specific point. However, without knowing the precise point of application, we cannot provide an exact answer to the question.
Therefore, the correct answer requires more information about the point where the force is applied on the door.