Math
posted by russell .
I have a problem.....
4(2x3)=8x+5
I understand first you distribute the 4 so you would have
8x+12=8x+5
Then if you try and move x over to either side you completley get rid of x.... am I missing something or is this problem not solvable?
Thank you
I think I just solved my own question :)
there is no solution....I just remember that is a possibility.
I was stuck in the mindset that there is always a solution, but I could not find it lol
Actually, there is a solution.
8x+12= 8x + 5
subtract 8x from both sides...
8x8x+12=5
now subtract 12 from both sides...
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