# Math

posted by .

I have a problem.....

-4(2x-3)=-8x+5

I understand first you distribute the -4 so you would have

-8x+12=-8x+5

Then if you try and move x over to either side you completley get rid of x.... am I missing something or is this problem not solvable?

Thank you

I think I just solved my own question :)

there is no solution....I just remember that is a possibility.

I was stuck in the mindset that there is always a solution, but I could not find it lol

Actually, there is a solution.

-8x+12= 8x + 5
subtract 8x from both sides...
-8x-8x+12=5
now subtract 12 from both sides...

## Similar Questions

1. ### math

3(4u-6)=2(4u-3)-(u-8) what is u 12u-18=8u-6-u+8 Can you take it from here?
2. ### geometry

i don't get how to do slope i know the equation but it never comes out right...do you have any advice to help me b/c i ask some people and they don't get it either and we have a test tomorrow?
3. ### algebra--distributive

how would you do this prob. negative4-(5y+6) = negative 7y+3 thanks. happy halloween I'm going to assume your problem is this: -4 - (5y + 6) = -7y + 3 If that's the case, distribute the negative over the terms in the parentheses first: …
4. ### math dealing with varibles

solve this problem S-46=14 is it... a)34 b)31 c)32 d)none of the above do you know how to solve for S?

3x^2+17x+10 *You have to factor completley but I don't know how too.Please help.! (3x+2 )(x + 5) Factoring asks this question: what two factors of 10 add to 17 when one is multiplied by three?
6. ### Math Help

3x^2 + 17x + 10 *I really don't get this but you have to factor completley. (3x+2)(x+5) thanks. - can you help me with my other problems.?
7. ### Marie

Maurice drove 400 km from Edmonton to Battleford in 1 hour less time than it took Martin to drive the same route from Battleford to Edmonton. If Maurice drove 20 km/h faster than Martin, at what speed did each of them drive?
8. ### Math

8*2sq+7*(4+1)= ? Can someone explain to me what to after the parenthesis?
9. ### Dividing Rational Expressions

x^3-8/x^2-4 divided by (x^2+2x+4)/(x^3+8). This becomes ((x-2)(x^2+2x+4)/(x+2)(x-2) times ((x+2)(x^2-2x+4))/(x^2+2x+4). I understand that (x-2)(x^2+2x+4)=(x^3-8) when I distribute it, however, if I didn't have the help of my book, …
10. ### Pre-Calculus

I think I need help with this problem- 3+ square root(x-6) = square root of (x+9) I thought I should square everything to get rid of square root signs so I had 9 + x-6 = x+ 9 then I would have x+ 3once I subtracted 9-6 from the left …

More Similar Questions