I have a problem.....
-4(2x-3)=-8x+5
I understand first you distribute the -4 so you would have
-8x+12=-8x+5
Then if you try and move x over to either side you completley get rid of x.... am I missing something or is this problem not solvable?
Thank you
I think I just solved my own question :)
there is no solution....I just remember that is a possibility.
I was stuck in the mindset that there is always a solution, but I could not find it lol
Actually, there is a solution.
-8x+12= 8x + 5
subtract 8x from both sides...
-8x-8x+12=5
now subtract 12 from both sides...
Actually, there is an error in your calculation.
Let's go through the steps correctly:
Start with the equation: -4(2x - 3) = -8x + 5
Distribute -4 to the terms inside the parentheses:
-8x + 12 = -8x + 5
Now, the next step is to bring the variable terms on one side and the constant terms on the other side. In this case, you have -8x terms on both sides, so they can cancel out when you subtract -8x from both sides:
-8x - 8x + 12 = -8x - 8x + 5
Simplifying it, you get:
-16x + 12 = 5
Next, you want to isolate the variable term, which is -16x. In order to do that, you need to get rid of the constant term of 12. Subtract 12 from both sides:
-16x + 12 - 12 = 5 - 12
This simplifies to:
-16x = -7
Finally, to solve for x, divide both sides by -16:
x = (-7) / (-16)
Simplifying it further:
x = 7/16
So, the solution to the equation -4(2x - 3) = -8x + 5 is x = 7/16.
Therefore, there is a solution to this equation.