physics
posted by Cavin .
A bowling ball encounters a 0.76m vertical rise on the way back to the ball rack. Ignore frictional losses and assume that the mass of the ball is distributed uniformly. If the translational speed of the ball is 3.80m/s at the bottom of the rise, find the translational speed at the top.
I will be happy to critique your thinking or work on this. Remember the ball has translational energy and rotational energy.
sum force= 0
therefore TF+TRAY+PLATE+CUP
T=1/.04(.240kg(.1m)+(.14m)(1.00kg)+(.28m)(.300kg)=6.2N
Please check my working
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