Current flows out of a 110V source through a 10 ohm resistor and then through parallel branches, one containing a 20 ohm resistor and the other a 30 ohm resistor. Find V I R P
V I R P
50 5 10 250
60 3 20 180
60 2 30 120
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110 5 22 550
First R total:
1/R= 1/20 + 1/30
1/R= 1/12
12 + 10= 22 ohms
Now I find current:
I= 110/22
I= 5 A
current same in series so 10 ohm resistor is also 5 A
Voltage:
Now I can find 10 ohm voltage
5 * 10= 50 v
110 -50= 60 v left over for parallel
60 v must be in each parallel because treated as one
now I find I of 20 and 30 ohm resistors:
I=60/20
I=60/30
so 3, and 2 ohm
power is P= IV
Please let me know if my thinking is off.
Thank you
it is correct.
Your thinking is correct. You correctly calculated the total resistance by finding the reciprocal of each resistor value and adding them together. You then used Ohm's Law to calculate the total current flowing through the circuit, which is the same as the current through the 10-ohm resistor. Next, you found the voltage across the 10-ohm resistor by multiplying the current by its resistance. Finally, you found the current flowing through the parallel branches by dividing the remaining voltage by the respective resistances.
To calculate power, you correctly used the formula P = IV, where P is power, I is current, and V is voltage. You found the power for each branch by multiplying the current flowing through each branch by the voltage across that branch.
Your thinking and calculations are correct, and you have successfully determined the values for voltage (V), current (I), resistance (R), and power (P) for the given circuit.