Four 20-ohm resistors are connected in series and the combination is connected to a 20 V emf device. The current in any one of the resistors is:

A) .25 A
B) 1.0 A
c) 4.0 A
D) 5.0 A
E) 100 A

My answer: A
R= 20 + 20 + 20 + 20 =80
V= IR
20/80=I
I=.25

A battery with an emf of 24 V is connected to a 6 ohm resistor. As a result, current of 3 A exists in the resistor. The terminal potential diference of the battery is:
A)0
B) 6 V
c) 12 V
D) 18 V
E) 24 V

My answer is D 18V. It wants to know the terminal resistance so V=IR or
V=6 *3= 18 V

Thank you

correct

Well, aren't you just a bright bulb! You got both answers right! A+ for electrical knowledge! Keep shining, my friend!

Yes, you are correct for both answers.

For the first question, when resistors are connected in series, the total resistance is the sum of individual resistances. So, R = 20 + 20 + 20 + 20 = 80 ohms. Since the emf device has a potential difference of 20V, we can use Ohm's Law (V = IR) to find the current in any one of the resistors. I = V/R = 20/80 = 0.25 A.

For the second question, you are again using Ohm's Law (V = IR). Given that the resistor has a resistance of 6 ohms and a current of 3 A, we can find the terminal potential difference of the battery. V = IR = 6 * 3 = 18 V.

Well done!

Yes, you are correct in both answers. Let's go through the steps to find the answers to each of the questions.

Question 1:
In this question, we have four 20-ohm resistors connected in series, and the combination is connected to a 20 V emf device. We want to find the current in any one of the resistors.

To find the current, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.

In this case, the total resistance (RT) of the series combination is equal to the sum of the resistances of the individual resistors. So, RT = 20 + 20 + 20 + 20 = 80 ohms.

Given that the emf device has a voltage of 20 V, we can apply Ohm's Law to find the current (I) in any one of the resistors using the formula I = V / R.
So, I = 20 V / 80 ohms = 0.25 A.

Therefore, the current in any one of the resistors is 0.25 A, which corresponds to option A.

Question 2:
In this question, we have a battery with an electromotive force (emf) of 24 V connected to a 6-ohm resistor. We are given that a current of 3 A exists in the resistor, and we want to find the terminal potential difference of the battery.

The terminal potential difference (V) of the battery is the voltage across the battery terminals. In this case, it is equal to the emf of the battery. We need to find the terminal potential difference.

To find the terminal potential difference, we can again use Ohm's Law. Rearranging the formula V = IR, we get V = I * R.

Given that the current (I) is 3 A and the resistance (R) is 6 ohms, we can substitute these values into the formula to find the terminal potential difference (V):
V = 3 A * 6 ohms = 18 V.

Therefore, the terminal potential difference of the battery is 18 V, which corresponds to option D.