I trust you know about y = mx + b
Realize that when you are given the x or y intercepts, you are really just given two points, in your case the points (4,0) and (0,-2)
So it is easy to find the slope, (-2-0)/(0-4) = 1/2
Take it from there
Determine the point-slope form of the line and the slope-intercept form of the line with x-intercept = 4 and y-intercept = -2
To determine the point-slope form of the line, we can use one of the given points (4,0) and the slope we found, which is 1/2.
Point-slope form of a linear equation is given by: y - y1 = m(x - x1)
Using (4,0) as the point and 1/2 as the slope, we substitute the values into the equation:
y - 0 = (1/2)(x - 4)
Simplifying gives us the point-slope form:
y = (1/2)x - 2
To determine the slope-intercept form of the line, we need to convert the equation to the form y = mx + b, where m is the slope and b is the y-intercept.
From the point-slope form, we can rearrange the equation to isolate y:
y = (1/2)x - 2
Comparing this form with the slope-intercept form, we see that the slope is 1/2, and the y-intercept is -2.
Hence, the slope-intercept form of the line is:
y = (1/2)x - 2