trig

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express this in sinx
(1/ cscx + cotx )+ (1/cscx- cotx)

i got 2sinx is that right??

and B)
express in cosx

problem: is 1 + cotx/cscx - sin^2x

i get to the step of 1 + cos-sin^2x and im stuck..help!


(1/cscx + cotx) + (1/cscx - cotx) =

(sinx + cosx/sinx) + (sinx - cosx/sinx) =

2sinx

You are correct on that one!

Note: 1 - sin^2x = cos^2x

1 + cotx/cscx - sin^2x =

1 + cosx - sin^2x =

cos^2x + cosx

...or...

cosx (cosx + 1)

I hope this helps.

somebody posted the same question before, but they had it as

1/(cscx+cotx) + 1/(cscx - cotx)

this would reduce to 2csc x
which in terms of sinx would be 2/sinx

  • trig -

    csc2x + 1 = 0

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