algebra1

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two consecutive integers such that the sum of 3 times the frist integer and 6 times second integer is 24. Expalin the variables that you used. If I could get help in solving this ASAP, I wiould really appreicate it?

Let the two consecutive integers be x and x =1. The verbal statements about the sum can be written
3 x + 6(x+1) = 24
Solve that.
The first step might me to rewrite it
9x + 6 = 24
Take it from there.

  • algebra1 -

    first of all it would be 3x+6x+1 then combine like terms to get 9x+1 then i don't know someone else help her please

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