two consecutive integers such that the sum of 3 times the frist integer and 6 times second integer is 24. Expalin the variables that you used. If I could get help in solving this ASAP, I wiould really appreicate it?
Let the two consecutive integers be x and x =1. The verbal statements about the sum can be written
3 x + 6(x+1) = 24
Solve that.
The first step might me to rewrite it
9x + 6 = 24
Take it from there.
first of all it would be 3x+6x+1 then combine like terms to get 9x+1 then i don't know someone else help her please
To solve this problem, let's define the variables.
Let's say the first integer is "x" and the second integer is "x + 1" (since they are consecutive integers).
Now, according to the given information, the sum of 3 times the first integer and 6 times the second integer is 24. So we can write it as an equation:
3x + 6(x + 1) = 24
To simplify the equation, we distribute the 6 to both terms inside the parentheses:
3x + 6x + 6 = 24
Combining like terms, we get:
9x + 6 = 24
Now, to solve for x, we want to isolate the variable on one side.
First, we subtract 6 from both sides of the equation:
9x = 24 - 6
Simplifying further, we have:
9x = 18
Finally, we divide both sides of the equation by 9 to solve for x:
x = 18 / 9
Simplifying this, we find:
x = 2
So the first integer is 2, and the second integer is x + 1 = 2 + 1 = 3.
Therefore, the two consecutive integers that satisfy the given condition are 2 and 3.