# Algerbra

posted by
**Tony**
.

how do you solve

7(3x+4)=8(2x+5)+13

expand the parenthesis...I will do the left side..

21x + 29=

Now, subtract sixteen x from both sides, and subtract 28 from both sides.

I will be happy to check your work.

7(3x+4)=8(2x+5)+13

21x + 29

is 7 times 4 28?

21x+ 28= 16x+40+13

21x+28= 16x+ 53

21x+28-28 = 16x+53-28

21x-16x= 16x-16x+25

5x= 25

do I divide now?

5x/5 =25/5

x=5

am I right?

you are right. Good work.