how do you solve

7(3x+4)=8(2x+5)+13

expand the parenthesis...I will do the left side..

21x + 29=

Now, subtract sixteen x from both sides, and subtract 28 from both sides.

I will be happy to check your work.


7(3x+4)=8(2x+5)+13
21x + 29

is 7 times 4 28?

21x+ 28= 16x+40+13
21x+28= 16x+ 53
21x+28-28 = 16x+53-28
21x-16x= 16x-16x+25
5x= 25
do I divide now?
5x/5 =25/5
x=5

am I right?

you are right. Good work.

2 (x-3 ) -3 (x +5 ) =3 ( x-2 ) -7

h(x)=3x=5x-3

Yes, you are correct! Let's go through the steps to solve the equation:

1. Start by expanding the parentheses on both sides:
7(3x+4) = 8(2x+5) + 13
This gives us: 21x + 28 = 16x + 40 + 13

2. Combine like terms on the right side of the equation:
16x + 40 + 13 = 16x + 53

3. Now, we want to isolate the variable x. To do this, we need to get rid of the constants on the right side and simplify the equation:
21x + 28 - 28 = 16x + 53 - 28
Simplifying further: 21x = 16x + 25

4. Now, we want to get all the x terms on one side of the equation. To do this, let's subtract 16x from both sides:
21x - 16x = 16x - 16x + 25
Simplifying further: 5x = 25

5. Finally, to solve for x, divide both sides of the equation by 5:
5x/5 = 25/5
Simplifying further: x = 5

So, the solution to the equation is x = 5. Well done!