Math
posted by Tony .
Rose's garden is in the shape of a trapezoid. If the height of the trapezoid is 16m, one base is 20m and the area is 224m2, what is the length of the other base?
The area of a trapezoid is:
A= (1/2) h (b1 + b2)
...where h = height and b1, b2 are the bases.
Substitute what you know to solve for the unknown.
224 = (1/2)(16)(20 + x)
Hopefully, you can solve for x, which will be the other base.

224= 16(20+b2)
2x224= 320+b2/2x2
Since 320+b2 over 2 has to multiply by 2 to get rid of the denominator, 224(area), has to also multiply by 2.
448=320+b2/2
320 divided by 2 is 160
448 divided by 2 is 224 again.
224=160
b2=160
Second base equals 160
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