Find the vertex of the function y = –x2 + 2x + 8.
it shows me different points as the answer.
Im not sure how to find that point. Here are the points: (1,7) or (1,9) or (4,-2) or (-1,-9)
Answered in a previous post. Here it is again:
Here's a quick way to find the vertex.
Use the format: [-b/2a, (4ac-b^2)/4a]
a = -1, b = 2, and c = 8
Substitute the values to find (x, y).
This will be your vertex.
To find the vertex of the function y = -x^2 + 2x + 8, you can use the formula [-b/2a, (4ac-b^2)/4a].
In this case, a = -1, b = 2, and c = 8. Plug in these values:
x = -2 / 2*(-1) = -2 / -2 = 1
To find the corresponding y-value, substitute x = 1 back into the original equation:
y = -(1)^2 + 2(1) + 8 = -1 + 2 + 8 = 9
Therefore, the vertex of the function is (1, 9).
The other points you listed (1, 7), (4, -2), and (-1, -9) are not correct for this function.