Algebra

posted by .

please solve

x+5y=10
-2x-10y=-20

Since the second equation can be obtained from the first (by multiplying both sides by -2), they are not independent and there is no unique solution. There are an infinite number of x,y combinations that are solutions.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra

    Solve the system 9x-5y=119 18x-10y=238 Double both sides of the first equation and you have 18x-10y =238 which is the same as the second equation. Since the two equations are not independent, there are no unique solutions. Thee are …
  2. MATH PLEASE CHECK IT!!2

    m-2/m-5*m+5/m-2=-1 If your problem is this: (m - 2)/(m - 5) * (m + 5)/(m - 2) = -1 (m - 2) cancels out in both the numerator and denominator on the left-hand side since you are multiplying. That leaves us with this: (m + 5)/(m - 5) …
  3. Algebra

    I am trying to solve the sytems of equations using the elimination method. 2x+4y=10 -3x+3y=-6 I tied multiplying the first equation by 2 and the second by 4. Then I tried multiplying the first equation by -3 and the secondy by 3. The …
  4. Math

    Graph the solution: 3x-y-7<0 x+5y+3>=0 This is my thought process in this: The first equation I can solve for y since we don't have to worry what x is. And I get y>3x-7. The second one, however, y is being multiplied by 5, …
  5. algebra

    Solve using the elimination method. Show your work. If the system has no solution or an infinite number of solutions, state this. -5x – 7y = 25.5 -2x + 10y = -9
  6. Algebra

    Solve using the substitution method. Show your work. If the system has no solution or an infinite number of solutions, state this. x + 10y = 41 x + 9y = 37
  7. algebra

    Solve using the substitution method. Show your work. If the system has no solution or an infinite number of solutions, state this. x + 10y = 41 x + 9y = 37
  8. Algebra

    Solve using the elimination method.Show work.If the system has no solution or an infinite number of solutions state this. 7x+8y=51,7x+10y=55
  9. simultaneous equations

    Solve 2a + b = 3 4a - 5b = 20 My attempt Multiply the first equation by 5 So, 10a + 5b = 15 4a - 5b = 20 Add them together 14a = 35 Divide both sides by 14 a = 2.5 Substitute (I have done it with the second one) 10 - 5b = 20 Take away …
  10. simultaneous equations

    Solve 2a + b = 3 4a - 5b = 20 My attempt Multiply the first equation by 5 So, 10a + 5b = 15 4a - 5b = 20 Add them together 14a = 35 Divide both sides by 14 a = 2.5 Substitute (I have done it with the second one) 10 - 5b = 20 Take away …

More Similar Questions