hi i rearranged these terms into y=mx+b can you plz check and see if they're right?

1. 2x+5y-16=0
2. 4x-3y-6=0
3. 3x+y+2=0

1. 5y=-2x+16
2.3y=-4x+6
3. y= -3x-2

tnx ^^

On the first two, you need to divide each side by the coefficent of y.
On two, what happened to the negative sign in front of 3y? On the first, all you have to do is divide both sides by 5.

Let's go through each equation and rearrange them into the form y = mx + b:

1. 2x + 5y - 16 = 0
To rearrange this equation, we need to isolate the term with y. First, let's move the 2x and -16 terms to the other side of the equation:
2x + 5y = 16
Now, to isolate y, we need to get rid of the 2x term. We can do this by subtracting 2x from both sides of the equation:
5y = -2x + 16
Finally, to get y by itself, we divide every term by the coefficient of y, which is 5:
y = (-2/5)x + 16/5
So, the correct rearrangement of the first equation is y = (-2/5)x + 16/5.

2. 4x - 3y - 6 = 0
To rearrange this equation, we follow a similar process. First, let's move the 4x and -6 terms to the other side of the equation:
4x - 3y = 6
To isolate y, we need to get rid of the 4x term. We can do this by subtracting 4x from both sides of the equation:
-3y = -4x + 6
Watch out for the negative sign. Now, to get y by itself, we divide every term by the coefficient of y, which is -3:
y = (4/3)x - 2
So, the correct rearrangement of the second equation is y = (4/3)x - 2.

3. 3x + y + 2 = 0
To rearrange this equation, we proceed as before. Let's move the 2 and 3x terms to the other side of the equation:
y = -3x - 2
So, the third equation is already in the form y = mx + b. However, it seems you made a mistake in the sign of the equation. It should be y = (-3x) - 2 instead of y = -3x - 2.

Thus, the correct rearrangements of the equations are:

1. y = (-2/5)x + 16/5
2. y = (4/3)x - 2
3. y = -3x - 2