from the balanced equation 4NH3 +7O2 - 4NO2 + 6H2O.
How many grams of oxygen are necessary to produce 4.50 moles of NO2?
I think its 11 grams or 22 grams but im not sure. please help!!
First the number of moles of O2,
molesO2= (4/7) moles NO2
Notice those came from the balanced equation.
Put in 4.5 moles NO2, and you have moles of O2.
Grams of O2? multiply moles of O2 by 32.
what do you mean I don't understand any of what you said execpt for Grams of O2? multiply moles of O2 by 32. sorry
Grams of O2 = moles of O2 x molar mass of O2
Molar mass of O2 = 32 g/mol
Therefore, 4.50 moles of NO2 requires 11 grams of O2.
I apologize for any confusion. I'll break it down step-by-step for you.
1. From the balanced equation 4NH3 + 7O2 -> 4NO2 + 6H2O, we can see that for every 7 moles of O2, we produce 4 moles of NO2.
2. We are given that we want to produce 4.50 moles of NO2. We can set up a proportion to find the moles of O2 needed.
(moles of O2) / (moles of NO2) = (7 moles O2) / (4 moles NO2)
Let's substitute the given value into the equation:
(moles of O2) / (4.50 moles NO2) = (7 moles O2) / (4 moles NO2)
3. Cross-multiplying the equation, we get:
(moles of O2) * (4 moles NO2) = (7 moles O2) * (4.50 moles NO2)
4(moles of O2) = 31.5 moles O2
Divide both sides by 4:
(moles of O2) = 31.5 moles O2 / 4
(moles of O2) = 7.875 moles O2
4. Finally, to convert moles of O2 to grams of O2, we multiply by the molar mass of O2, which is 32 g/mol:
(grams of O2) = (moles of O2) * (molar mass of O2)
(grams of O2) = 7.875 moles O2 * 32 g/mol
(grams of O2) ≈ 252 grams of O2
Therefore, the amount of oxygen necessary to produce 4.50 moles of NO2 is approximately 252 grams.
I apologize for the confusion. Let me explain step by step how to calculate the grams of oxygen required to produce 4.50 moles of NO2.
1. Start with the balanced equation:
4NH3 + 7O2 -> 4NO2 + 6H2O
2. From the equation, we can see that 4 moles of NH3 react with 7 moles of O2 to produce 4 moles of NO2.
3. Use the stoichiometric ratios from the balanced equation to find the moles of O2 required to produce 4 moles of NO2. Since the ratio of O2 to NO2 is 7:4, we can calculate:
moles of O2 = (7/4) * moles of NO2
In this case, we want to find the moles of O2 required to produce 4.50 moles of NO2. So:
moles of O2 = (7/4) * 4.50 moles of NO2
4. Now, to find the grams of O2, we need to multiply the moles of O2 by the molar mass of O2. The molar mass of oxygen (O2) is 32.00 g/mol.
grams of O2 = moles of O2 * molar mass of O2
= moles of O2 * 32.00 g/mol
So, to calculate the grams of O2 needed to produce 4.50 moles of NO2, you can follow these steps:
1. Calculate moles of O2 by using the formula: moles of O2 = (7/4) * 4.50 moles of NO2
2. Multiply moles of O2 by the molar mass of O2 (32.00 g/mol) to get the grams of O2.
I hope this clarifies the steps involved in finding the answer to your question.