# basic geometry

posted by
**vero**
.

The length of a rectangular picture is seven iches longer than the width. Find the length and the width if the perimeter of the picture is 62 inches.

2L+2w=62

2L+2w+7=62

4L+7 =62

4L=7+62

4L=69

4L=69/4

2L+2w=62 **You are ok to here.
length is 7" longer than the width; therefore, L = w+7, so
2(w+7)+ 2w = 62**

2L+2w+7=62

4L+7 =62

4L=7+62

4L=69

4L=69/4

I don' t understand the rest of the problem would it be

2L+2w=62

L =w+7

2(w+&0+2=62

2w+7+2=62

11w=62

w=11+62

w=78