The length of a rectangular picture is seven iches longer than the width. Find the length and the width if the perimeter of the picture is 62 inches.
2L+2w=62
2L+2w+7=62
4L+7 =62
4L=7+62
4L=69
4L=69/4
2L+2w=62 You are ok to here.
length is 7" longer than the width; therefore, L = w+7, so
2(w+7)+ 2w = 62
2L+2w+7=62
4L+7 =62
4L=7+62
4L=69
4L=69/4
I don' t understand the rest of the problem would it be
2L+2w=62
L =w+7
2(w+&0+2=62
2w+7+2=62
11w=62
w=11+62
w=78
To solve for the length and width of the rectangular picture, you can use the given information and the equation 2L + 2w = 62.
Let's break it down step by step:
1. The length of the rectangular picture is 7 inches longer than the width. So, we can represent the length as L and the width as w+7.
2. The formula for the perimeter of a rectangle is 2L + 2w. Since we know the perimeter is 62 inches, we can set up the equation 2L + 2w = 62.
3. Now, substitute L with w+7 in the perimeter equation. The equation becomes 2(w+7) + 2w = 62.
4. Simplify the equation: 2w + 14 + 2w = 62. Combine like terms: 4w + 14 = 62.
5. Subtract 14 from both sides to isolate the variable: 4w = 48.
6. Divide both sides of the equation by 4 to solve for w: w = 48/4 = 12.
7. Now that we have the value for w, we can find the length (L) by substituting it back into the expression L = w+7: L = 12 + 7 = 19.
Therefore, the length of the rectangular picture is 19 inches, and the width is 12 inches.