COMPOUND 1

CH2 = CH-CH-OH with CH3 under the second CH

Plus

CH3-CH-CH2-C (double bond O off C and -OH off C) also a CH3 under CH

i) complete the equation for this reaction
ii) Indentify any new functional groups in the organic product(s)name them

iii)State the type of reaction that has occured and explain how you arrived at the answer

A CH3 under the second CH from the left (or right) puts too many bonds on the carbon atom. Do you intend for the CH3 group to be attached to the C with the OH?
Look up uester formation. That is the reaction that will take place. Acids (RCOOH) plus alchols (R'OH) gives esters
(RCOOR')

i) To complete the equation for the reaction, we need to consider the reaction between the given compounds. Based on the information provided, we have:

Compound 1: CH2=CH-CH-OH with CH3 under the second CH
Compound 2: CH3-CH-CH2-C (double bond O off C and -OH off C) with CH3 under CH

The reaction between these compounds will involve the formation of an ester. Esters are formed through a reaction between an acid and an alcohol. In this case, Compound 1 contains an alcohol functional group (OH) and Compound 2 contains an acid functional group (C=O with -OH). The acid portion of Compound 2 will react with the alcohol portion of Compound 1 to form an ester.

Therefore, the reaction can be represented as:

Compound 1 + Compound 2 → Ester + Byproduct

ii) After the reaction, the organic product (the ester) will contain new functional groups. We need to identify these new functional groups and name them.

The ester functional group is characterized by the general formula RCOOR', where R and R' are alkyl groups. In this case, R and R' will come from the two compounds involved in the reaction. The specific names of R and R' will depend on the specific structures of Compound 1 and Compound 2. Without the exact structures, we cannot provide the specific names of the new functional groups.

iii) The type of reaction that has occurred is referred to as esterification. Esterification is a condensation reaction that involves the combination of an acid and an alcohol to form an ester, accompanied by the release of a molecule of water.

We arrived at this answer by analyzing the functional groups present in the starting compounds (alcohol and acid), and recognizing that the reaction between them would result in the formation of an ester. Esterification is a common reaction in organic chemistry, and the presence of an alcohol and acid functional groups in the reactants indicated that this reaction would occur.

The exact reaction conditions (catalyst, temperature, etc.) may affect the specifics of the reaction, but the overall process is esterification.