relative extrema

x^4-2x^2+5

so far I know how to find the derivative which is

4x^3-2x now I am stuck...
Please help

Huh?

4x^3-2x=0
2x(2x^2-1)=0
and what are the roots? I will give you a hint: one is x=0 The other two are in the second parenthesis.

Is it x-1 and x=-1

I did a typo

Is it

x-1, x+1

If you are in calc, you might want to consider some alternatives. This is pretty low level algebra. You are going to suffer with this lack of algebra understanding.

The roots of
2x(2x^2-1)=0
come from 2x=0 and 2x^2-1=0
or x=0 or x= +- sqrt (1/2)
Three roots.

Good luck.

The way that I did the problem was different than the way you did it. I had 4x(x^2-1) = 0

That is how I came up with the roots of x=0, x=1, x=-1

Was this way correct also?

No. You cannot factor 4x^3-2x the way you did. The only common factor is 2x.

4x^3-2x = 2x(2x^2-1)

The original problem was this

x^4-2x^2+5

Derivative = 4x^3-4x=0 when you factor you get 4x(x^2-1) = 0
Then you are left with x=0, x=1, x=-1.

I think you are given me the wrong answer.

he was starting from where you left off with your derivative. the first time you wrote "so far I know how to find the derivative which is

4x^3-2x now I am stuck...
Please help "
that derivative is wrong. it is simply the one he used, hence the wrong answer.

24X=260*(1.05^x/2)

I apologize for the confusion. Let me clarify the steps to find the relative extrema of the function x^4-2x^2+5.

1. Find the derivative of the function:
The derivative of x^4-2x^2+5 is 4x^3-4x.

2. Set the derivative equal to zero and solve for x:
4x^3-4x=0

To solve this equation, you can factor out 4x:
4x(x^2-1)=0

Now, you have two possibilities:

a) Set 4x = 0:
4x = 0
x = 0

b) Set x^2-1 = 0:
x^2-1 = 0
(x+1)(x-1) = 0

Setting each factor equal to zero, you get:
x+1 = 0 => x = -1
x-1 = 0 => x = 1

So, the roots of the derivative equation are x = -1, x = 0, and x = 1.

3. Find the corresponding y-values:
To find the corresponding y-values, substitute each x-value back into the original function:
For x = -1: (-1)^4-2(-1)^2+5 = 1-2+5 = 4
For x = 0: 0^4-2(0)^2+5 = 5
For x = 1: (1)^4-2(1)^2+5 = 1-2+5 = 4

Therefore, the relative extrema of the function occur at the points (-1, 4) and (0, 5).