Calculus
posted by Aurora .
Find the equation of the tangent to the graph of f(x)=2x^4 (to the power of 4) that has slope 1.
Derivative is 8 x^3. This equals 1 at
x = 1/2. At this point the ycoordinate is f(1/2) = 1/8. The equation of the tangent line is thus:
1/8 + 1*(x1/2) =
x  3/8
Thank you for your assistance.
It clarified my thinking in regards to similar questions.
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