Calculus

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Find the equation of the tangent to the graph of f(x)=2x^4 (to the power of 4) that has slope 1.

Derivative is 8 x^3. This equals 1 at
x = 1/2. At this point the y-coordinate is f(1/2) = 1/8. The equation of the tangent line is thus:

1/8 + 1*(x-1/2) =

x - 3/8

Thank you for your assistance.

It clarified my thinking in regards to similar questions.

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