Pre Calculus
posted by raven 31791 .
Find the roots of the function g(x)=x^3 +16x
a)0,4i, 4i
b)0,4,4i
c)0,4,4i
d)0,4,4
The equation can be rewritten
x(x^2 + 16) = 0
The function is zero if x = 0, OR if
x^2 = 16
That should give you a hint of what the roots are.
So you take the square root of 16 which gives you + 4 making the answer d. Right?
No. The square root of 16 is 4i and 41.
i = sqrt (1)
The answer is (a). I mistakenly typed
41 for 4i
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