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algebra

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use substitution to solve the linear system

3x+2y=-5
4x-3y=16

help plz!!!

Solve for y in one formula, and then substitute that value for y in the other formula to solve for x. Once you find x, substitute that value into either formula to get the value for y.

-3y = 16 - 4x

y = (16 - 4x)/-3 = (4/3)x - 16/3

I'll let you do the rest.

I hope this helps. Thanks for asking.

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