use substitution to solve the linear system
3x-y=15
x+2y=-2
Solve for y in one formula, and then substitute that value for y in the other formula to solve for x. Once you find x, substitute that value into either formula to get the value for y.
2y = -2 - x
y = (-2-x)/2 = -1 - x/2
I will let you do the rest.
I hope this helps. Thanks for asking.
To solve the linear system using substitution, follow these steps:
1. Start with the given equations:
3x - y = 15 [Equation 1]
x + 2y = -2 [Equation 2]
2. Solve one of the equations for a single variable, preferably expressing it in terms of the other variable. Let's solve Equation 2 for x:
From Equation 2, isolate x:
x = -2 - 2y
3. Substitute this expression for x in Equation 1:
3(-2 - 2y) - y = 15
4. Simplify the equation:
-6 - 6y - y = 15
-7y - 6 = 15
-7y = 15 + 6
-7y = 21
5. Divide both sides of the equation by -7 to get the value of y:
y = 21 / -7
y = -3
6. Substitute the value of y back into one of the original equations to solve for x. Let's use Equation 2:
x + 2(-3) = -2
x - 6 = -2
x = -2 + 6
x = 4
7. Now, you have found the values of x = 4 and y = -3, which satisfy both equations in the system.
So, the solution to the linear system using substitution is x = 4, y = -3.