# precalculus

posted by
**Roxanne**
.

(2y+1)(y+3)(5y-2)=0

If A x B x C=0, then A, B, or C are equal to zero. Therefore, for the problem, 2y+1=0

y+3=0

5y-2=0

Solving the equations for y will give the correct answers (three of them) for y.