algabra

posted by .

the sum of a the digits in a two digit # is 11. if the digits are reversed, the new # is 45 more than the original #. What is this # !!! i need help

AB is the two digit number

A+B=11
10B + A= 10A + B - 45

solve.

Ok, first.

You would first bring both sides of the equation to only one side. Combining the like terms. (A's goes with A's, B's go with B's, Etc).

So, considering it wont matter which way you put it, so lets say we did the left side.

Heres what it would like.

10B + A = 10A + B - 45

You would bring the 10A to the A on the left side. And since its positive on the right side you would have to do the opposite and subtract the 10A.

Heres what it would look like.

10B - 9A = B - 45

The reason why 9A is there is because when you subtract 1OA from 1A its like a regular math:

10
- 1
----
9

And so, that is the reason why you get the amount -9A.

Next, you would put the B to the other side as well.

Heres how it would look using the same way as to get the 10A over there.

9B - 9A = - 45

Remember, NEVER to drop out the - sign on the right side. It shows the number is a negative and without it your equation will be wrong.

If i can remember right, that's all you can do for basic algebra.

I hope that helped you out.

---James

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math ALGEBRA

    When the digits of two-digits numbers are reversed, the new number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number. Can some one please help me here?
  2. algebra

    hi... i need help finding 2 equations that i would use for this elimination process.... this is what they gave me: * the sum of the digits i a two-digit is 14. If the 2 digits are reversed, the new number is 18 less than the original …
  3. algebra..urgent...

    hi... i need help finding 2 equations that i would use for this elimination process.... this is what they gave me: * the sum of the digits i a two-digit is 14. If the 2 digits are reversed, the new number is 18 less than the original …
  4. Algebra 2

    The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number is 27 more than the original number. Find the original number. I hate silly word problems like this, please help me out.
  5. algebra

    A number consists of two digits. The sum of twice the tens digit an 5 times the units digit is 19. If the digits are reversed, the new number is 54 less than the original number. Find the number
  6. math

    the sum of the digits in a three-digit number is 16.the ones digit is three times the hundreds digit.if the digits of the number are reversed ,the new number is 594 more than the original .what is the original number?
  7. algebra

    the sum of the digits of a three digit number is 20. the middle digit is equal to one fourth the sum of the other two. if the order of the digits be reversed the number increases the original by 198 find the original number
  8. Algebra

    In a two-digit number the units’ digit is 7 more than the tens’ digit. The number with digits reversed is three times as large as the sum of the original number and the two digits. Find the number.
  9. Algebra PLEASE HELPPP ASAP NEED HELP!!!

    In a two-digit number the units’ digit is 7 more than the tens’ digit. The number with digits reversed is three times as large as the sum of the original number and the two digits. Find the number.
  10. Math

    The sum of digits of a three-digit number is 14, and the ten's digit of the number is one more than the unit's digit. If the digits were reversed in order, the new number is 198 more than the original. What is the original number?

More Similar Questions