Roots and Pre-cal

posted by .

Find the roots of the function
f(x)= x^2 +2x+2

a)-1 + sq root of 2 and -1 - sq root of 2

b) -1 + i and -1 - i

c)-1 -2i sq root of 2 and -1-2i sq root of 2

d)-1 +2i and -1-2i

The i's are in italics but I can't .make them in italic here for some reason



completing the square:
x^2+2x +1= -2 +1
(x+1)^2=-1
x+1= +-i sqrt2

solve for x

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Pre Calculus

    Find the roots of the function g(x)=x^3 +16x a)0,4i, -4i b)0,-4,-4i c)0,4,4i d)0,4,-4 The equation can be rewritten x(x^2 + 16) = 0 The function is zero if x = 0, OR if x^2 = -16 That should give you a hint of what the roots are. So …
  2. math

    Could you please solve so I can double check my answers for the practice quiz?
  3. math

    I HAVE THESE ANSWERS FOR THE PROBLEMS. COULD YOU DOUBLE CHECK PLEASE, THIS IS A PRACTICE QUIZ WHICH ISN'T A GRADE IT JUST HELPS ME GET READY FOR THE TEST. 1) a 2) b 3) d 4) a 5) d 1. Solve x^3 + 6x^2 + 13x + 10 = 0. a) –2 + 2i, –2 …
  4. Calculus I

    Find the derivative ** (sq root) y = (square root) x + (2nd sq root) x + (3rd sq root) x ** All the x's is under three sq roots y' = 1/2(sq rt) x + 1/(sq rt) x + 3/2(sq rt) x Is this right?
  5. College Algebra--Still Confused

    I have a few problems I need help with and also do have multiple choice. If I can have an explanation of how to get the answer that would be great. 1. Use the discriminant to determine whether the given equation has two irrational …
  6. mathematics

    Use the discriminant to determine the number of real roots the equation has. 3x2 – 5x + 1 =0 A. One real root (a double root) B. Two distinct real roots C. Three real roots D. None (two imaginary roots)
  7. maths2

    Use the discriminant to determine the number of real roots the equation has. 7x2 + 3x + 1 =0 A. One real root (a double root) B. Two distinct real roots C. Three real roots D. None (two imaginary roots)
  8. math

    Please help I'm so confused!!!! 1. Which two square roots are used to estimate the square root of 5?
  9. Pre-Calculus

    Solve. Express your answer as exact roots. (s+6)^2 = 3/4 Sq root (s+6)^2 = +-sq root 3/4 (s+6) = sq root 3/ 2 s = -6 +- sq root 3 ----------------- 2 (The answer according to the textbook is (-12 +- sq root 3)/2. What error have I …
  10. Pre-Calculus

    Solve 0 = 3x^2 + 5x -1 by completing the square. Express your answer as exact roots. 3(x^2 + 5/3 + 25/36) = -1 (x+ 5/6)^2 = 37/36 sq root( x + 5/6)^2 = sq root (37/36) x + 5/6 = +- sq root 37/6 x = -5/6 +- square root 37 /6 <--- …

More Similar Questions