Good evening. Thanks for all of your help so far. I posted a question on wednesday 28 Feb @ 11:55 pm that you answered by I am not sure of how to tackle the problem. This is what I came up with so far.
Mass of Puck A m1 = 0.021 kg
Mag. of init. veloc.of Puck A V01=5.5kg (before collision occurs)
Directional angle of init vel of A is 65 degrees
Mass of Puck B m2 = 0.041 kg
Mag. of init. veloc. of Puck B V02= 0 (before collision occurs)
Directional angle of final veloc. of Puck B 37 degrees (after collision occurs)
UNKNOWN VARIABLES
Mag. of final veloc. of Puck A (after collision occur)
Mag of final veloc. of Puck B (after collision occurs)
I AM UNSURE WHERE TO GO FROM HERE! Please help!
Again, write the momentum equations in the x and y directions.
Here is a sample y equation:
ma*va*sin65= ma*va'*sinTheta + mb*vb'*sin37
So there are three variables here: va', theta, vb'
Write the same equation in the x direction.
Finally, the conservation of energy gives you the third equation.
Lots of math.
Good evening! I'm glad I could assist you before, and I'll be happy to help you with this problem as well. From your description, it seems like you are working on a collision problem involving two pucks, A and B.
To solve this problem, you can use the principles of momentum conservation and energy conservation. Here's a step-by-step approach to tackle it:
1. Start by writing the momentum equations in the x and y directions. In this case, you've already written the y equation:
ma * va * sin(65°) = ma * va' * sin(θ) + mb * vb' * sin(37°)
Here, va is the magnitude of the initial velocity of puck A, va' is the magnitude of the final velocity of puck A, vb' is the magnitude of the final velocity of puck B, and θ is the angle of the final velocity of puck A.
2. Now, write the same equation in the x direction. This equation should include the cosine function:
ma * va * cos(65°) = ma * va' * cos(θ) + mb * vb' * cos(37°)
Remember to use the appropriate angles and cosine instead of sine.
3. The conservation of energy gives you the third equation. The initial kinetic energy will be equal to the final kinetic energy:
(1/2) * ma * va^2 = (1/2) * ma * va'^2 + (1/2) * mb * vb'^2
Here, ma and mb are the masses of pucks A and B, va and vb are the initial velocities of pucks A and B, and va' and vb' are their final velocities.
4. Now that you have three equations, va', θ, and vb' are the unknown variables to solve for. You can rearrange the equations and solve them simultaneously to find the values of these unknowns.
Note that the angles should be in radians, so make sure to convert them if necessary.
Remember, solving this problem requires a lot of calculations, so it's crucial to be organized and pay attention to units and algebraic operations. Take your time and double-check your work.
If you need further assistance or have any more specific questions about this problem, feel free to ask!