BobPursley..here it is:
posted by Margie .
Problem 1:
(x2)/(3x+4)  6x/(x+1)
What I did:
Common denominator is: (3x+4)(x+1)
(x2)(x+1)/(3x+4)(x+1)  6x(3x+4)/(x+1)(3x+4)
[(x2)(x+1)  6x(3x+4)] / (x+1)(3x+4)
(x^2  x  2  18x^2  24x) / (x+1)(3x+4)
x^2  18x^2 = 17x^2
x  24x = 25x
(17x^2  25x  2) / (x+1)(3x+4)
I don't see any errors.
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