This question is not well defined. By 'expi' do you mean exp(i)? In other words, is the expression [exp(i)]^i ? If so, then the answer is undoubtedly exp(-1). You can use Euler's equation to show this, but it is much easier to use this fact about exponents:

(a^b)^c=a^(bc).

On the other hand, if the function is expi, then I don't know what that function is.

It is important to use parentheses for clarity if you are writing mathematical expressions in ASCII.

sorry, the exact question was exp(i^i) and i found it! it is exp(-Ï€/2)=1.23
thanks anyway

sorry, the exact question was exp(i^i) and i found it! it is exp(-Ï€/2)=1.23
thanks anyway

No problem! I apologize for the confusion earlier. I'm glad you found the answer. The expression exp(i^i) evaluates to exp(-π/2), which is approximately equal to 1.23.

To get this answer, you raised the complex number i to the power of i, and then took the exponential of the result. The value of i^i is a complex number, and using Euler's formula, it can be represented as exp(-π/2). Finally, taking the exponential of exp(-π/2) gives us the approximate value of 1.23.