Math2[Please Check Again]

posted by .

Problem:
a^2-9 a^2-3a
----- * --------
a^2 a^2+a-12
What I Got:
3-3a
----
a-4
*Please Check My Work.*

Nope.

factor the denominator to a^2(a+4)(a-3)
The last factor divides out in the numerattor (second term factors to a(a-3). The a in the numerator reduces the denominaor a^2 term

I lost you afterthe last factor divides out the numerator.Which one?

In the numerator, either term will give you a-3 when factored.

So then:
3(a-3)
------
a(a+4)

Did you get your answer yet? Do you understand now?

No.-Can you help me please Mack.?

Margie,do you needy helpy?Do you speak espanol?

¿Sí, hablo español por qué?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Pre-Calculus

    How do you factor this completly 7x*(4x-5)^3+(4x-5)^4 I am confused by the different power of exponets and the 7x in front Can you please help me?
  2. math

    Shorten fraction: (x^2+2x)/(4x+8)= ? and reduce: (8a^3*b*a^-2)/(2b)^2= ?
  3. Math

    1.3x^2+17x+10 2.5y^8-125 3.a^2-2ab-15b^2 *Please help me.You have to factor by completing. Let's look at #1: 3x^2 + 17x + 10 We have 2 and 5 as factors of the last term. What combinations can we do to arrive at the middle term?
  4. Math(Please Check Again)

    25-x^2 6x^2 ------ * ------ 12 2x *I got: 5-x/2 No. Try again. Can you tell me what I did wrong please.?
  5. Please Check (Math2)

    a^2-9 a^2-3a ----- * ------- a^2 a^2+a-12 *I got: 3-3a/4 I don't think so. factor the a^2-9, and the second numerator to a(a-3) Then the denominator factored is a^2*(a+4)(a-3) So wait... don't I have to first have to take out the repeated …
  6. math,correction

    can someone check these for me please.... problem#4 Directions: Factor each polynomial completely by factoring out any common factors and then factor by grouping. Do not combine like terms. 3a^3+3ab^2+2a^2b+2b^3 My answer: (a^2+b^2)(3a+2b) …
  7. Math[PLease Check]

    Problem: 25-x^2 6 ------ * --- 12 5-x What I got: 5-x --- 2 *PLease Check My Work. No. Factor the 25-x^2 into two factors. Then the 5-x in the denominator divides out. So then is it: 5+x --- 2 yes. 12x12
  8. PLease Help Me IN Math

    Problem: 25-x^2 6 ------ * --- 12 5-x What I Got: 5-x --- 2 *Please Check My Work And Tell Me If I am Correct or wrong.If I am wrong please help me as much as possible.Thank you~ Wrong. When are you going to factor the 25-x^2 ?
  9. More Math 2 See If You Can Help Me... :)

    Problem: a^2-9 a^2-3a ----- * -------- a^2 a^2+a-12 Here Is What I Got: (a+3)3a ------- (a+4) *Please Check It.I think I did it wrong though.. =[ I'm going to assume your problem is this: (a^2-9)/a^2 * (a^2-3a)/(a^2+a-12) Note: I'm …
  10. Math...PLease Help Me...

    Problem: 6-3x 25 ---- * ---- 5 4x-8 *I have to multiply the expression and simplify it.Thanks for your help. The five goes into the twenty five, and you can factor out a three from the first term in the numerator, and a two from the …

More Similar Questions