maths
posted by em .
Hi, could someone please tell me how I would go about working these out: (the answer must be in the form a(sqroot)b where a and b are integers and b is as small as possible.)
1) Simplify (sqroot)500
2) Simplify (sqroot)50 x (sqroot)60
Also..
Simplify the following fractions so that there is no root in the denominator:
1/(sqroot)5
12/(sqroot)3
Thankyou so much!
1) sqrt500 =sqrt(25 x4 x 5)
=(sqrt 25)x(sqrt4)x (Sqrt5)
=5 x 2 x (sqrt5)
=10sqrt5
therefore a=10 and b=5
2) sqrt50 xsqrt60 =Sqrt300
=sqrt25 x sqrt4 x sqrt3
=5 x 2 x sqrt3
=10sqrt3
therefore a=10 and b=3
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