# maths

posted by
**em**
.

Hi, could someone please tell me how I would go about working these out: (the answer must be in the form a(sqroot)b where a and b are integers and b is as small as possible.)

1) Simplify (sqroot)500

2) Simplify (sqroot)50 x (sqroot)60

Also..

Simplify the following fractions so that there is no root in the denominator:

1/(sqroot)5

12/(sqroot)3

Thankyou so much!

1) sqrt500 =sqrt(25 x4 x 5)

=(sqrt 25)x(sqrt4)x (Sqrt5)

=5 x 2 x (sqrt5)

=10sqrt5

therefore a=10 and b=5

2) sqrt50 xsqrt60 =Sqrt300

=sqrt25 x sqrt4 x sqrt3

=5 x 2 x sqrt3

=10sqrt3

therefore a=10 and b=3