Can you help me with balacing this equation:
potassium chromate + iron nitrate yeilds potassium nitrate + iron chromate
I will be happy to critique your work on this.
Okay so . . .
I start off writing the equation equation like so
K2CrO4 + FeNO3 YEILDS KNO3 + Fe2(CrO4)3
I think I got it.... is it
3K2CrO4 +2Fe(NO3)3 yeilds 6KNO3 + Fe2(CrO4)3
To balance the given equation of potassium chromate + iron nitrate yields potassium nitrate + iron chromate, let's go step by step:
1. Count the number of atoms for each element on both sides of the equation.
On the reactant side:
- Potassium (K): There are 2 potassium atoms on the left.
- Chromium (Cr): There is 1 chromium atom on the left.
- Oxygen (O): There are 4 oxygen atoms on the left.
- Nitrogen (N): There is 1 nitrogen atom on the left.
On the product side:
- Potassium (K): There are 6 potassium atoms on the right.
- Chromium (Cr): There are 3 chromium atoms on the right.
- Oxygen (O): There are 12 oxygen atoms on the right.
- Nitrogen (N): There are 4 nitrogen atoms on the right.
2. Determine which elements are unbalanced.
Looking at the elements, we can see that potassium (K), chromium (Cr), and nitrogen (N) are unbalanced.
3. Start balancing the equation by adjusting the coefficients of the molecules.
Let's balance the potassium atoms first. To get 6 potassium atoms on the reactant side, we need to multiply K2CrO4 by 3.
3K2CrO4 + Fe(NO3)3 --> ...
Now, let's balance the nitrogen atoms. To get 6 nitrogen atoms on the product side, we need to multiply KNO3 by 2.
3K2CrO4 + Fe(NO3)3 --> 6KNO3 + ...
Finally, let's balance the chromium atoms. To get 3 chromium atoms on the product side, we need to multiply Fe(NO3)3 by 2.
3K2CrO4 + 2Fe(NO3)3 --> 6KNO3 + ...
The balanced equation is:
3K2CrO4 + 2Fe(NO3)3 yields 6KNO3 + Fe2(CrO4)3
So, your balanced equation is correct:
3K2CrO4 + 2Fe(NO3)3 yields 6KNO3 + Fe2(CrO4)3
I hope this helps, and please let me know if you have any further questions or need clarification!