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a^2-9 a^2-3a
----- * -------
a^2 a^2+a-12
*I got:
3-3a/4

I don't think so.

factor the a^2-9, and the second numerator to a(a-3)
Then the denominator factored is
a^2*(a+4)(a-3)

So wait...
don't I have to first have to take out the repeated thingys.?

I don't know what repeated things means. Factor the numerator, and the denominator. Divide out common terms, and reduce. Ohhhh. on the second numerator, you can factor out an a, as I showed above.

I mean take out the common terms...sorry

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