Please Check (Math2)
posted by Margie .
a^29 a^23a
 * 
a^2 a^2+a12
*I got:
33a/4
I don't think so.
factor the a^29, and the second numerator to a(a3)
Then the denominator factored is
a^2*(a+4)(a3)
So wait...
don't I have to first have to take out the repeated thingys.?
I don't know what repeated things means. Factor the numerator, and the denominator. Divide out common terms, and reduce. Ohhhh. on the second numerator, you can factor out an a, as I showed above.
I mean take out the common terms...sorry
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