Math Repost!!Please Help!!!!
posted by steve the hippo .
6y

y^22724
well it should simplify to
(6y)/(y^1)
which then changes to y(6y)
which then equals y(6y)=0
then you set both parts equal to zero and solve for xero
y=0 and/or (6y)=0
so y=0 or y=6
Did you mean for this problem to be this:
6  y

y^2  2y  24
If so, factor wherever you can in order to reduce as much as you can.
The denominator as I typed it will factor this way:
(y  6)(y + 4)
Now we have this:
6  y

(y  6)(y + 4)
Factor out 1 in the numerator:
1(y  6)

(y  6)(y + 4)
You can cancel out (y  6) in both the numerator and denominator to reduce.
You are then left with this:
1

(y + 4)
And that's as far as we can go here!
I hope this helps and is what you were asking.
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