A gasoline engine runs with 28 percent efficiency. It expels 3.60x10^4 J of heat in each cycle.
a. Find the heat absorbed in one cycle.
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b. Find the work output in one cycle.
To solve this problem, we can use the concept of energy efficiency, specifically the efficiency of a heat engine. The efficiency of a heat engine is defined as the ratio of the work output to the heat absorbed. It can be calculated using the formula:
Efficiency = (Work output / Heat absorbed) * 100
The given efficiency of the gasoline engine is 28 percent, which can be converted to a decimal as 0.28.
a. To find the heat absorbed in one cycle, we can rearrange the formula for efficiency as follows:
Heat absorbed = (Work output / Efficiency) * 100
The work output is not given, so we cannot directly calculate the heat absorbed. However, we can calculate the work output using the given information.
b. The work output in one cycle can be found using the formula:
Work output = Heat absorbed * Efficiency
Given:
Efficiency = 0.28
Heat expelled in one cycle = 3.60 x 10^4 J
Using the equation above, we substitute the given values to find the work output:
Work output = (3.60 x 10^4 J) * (0.28)
= 1.008 x 10^4 J
Therefore, the work output in one cycle is 1.008 x 10^4 J.