a. State the atomic number of ununhexium and give the full symbol for the isotope ununhexium.
b. Give the period and the group of the periodic table in which you would expect to find ununhexium, explaining how you arrived at your conclusions. Further name one other chemical element that you would expect ununhexium to resemble closely.
c. Give the Emperical formulae of the highest hydride and highest fluoride of ununhexium explaining how you arrived at your conclusion.
d. Suppose that the isotope of ununhexium undergoes a succession of seven alpha - decay reactions.
d1. What isotope would be the final product of these changes? show how you arrived at your answer
d2. Is the final product a lanthanide, an actinide, a transition element or a typical element?
Many thanks for your assistance Dr Bob, I have the highest regard and respect for anyone who can master this subject...I am struggling a little.
so am i i take it you are on s103 block 6 have you managed to look at block 7 yet
Not at this time Sir no.. I am trying to assist my partner who is on this program. Currently she is finding it quite difficult, math being her gremlin, I'm trying to learn this to help and support her, but unformtunately this is not my area of specialty. I was writing this merely responding to the response you gave to another lad, where you stated if he wrote the question you might be able to help further. i thought i would save him some time as I couldn't find the questions posted anywhere.
Many thanks for your help Sir...
Mark Jones
IT Training Manager.
First, some rules of this board. We don't DO homework. We HELP do homework. I can give you some hints to get you and your partner started. You don't learn this subject except by doing it. Here are some very good hints. Be sure and post back with your thoughts and we can go from there. It would be good to have your partner post so I will know her thoughts as well as yours.
a. State the atomic number of ununhexium and give the full symbol for the isotope ununhexium.
The symbol for ununhexium is Uuh and its atomic number is 116. I take it that what you mean by the full symbol for the isotope is the mass number as well but there isn't enough information here to obtain that. However, go to www.webelements.com (a web periodic table) and click on element #116. That will give you a great deal of information about Uuh.
Then you will write the full symbol as
116Uuh292 or whatever you find for the mass number if it isn't 292. By the way, technically, the mass number goes as a superscript TO THE LEFT of the symbol but it's difficult on the computer to make both subscript (for the atomic number) and superscript (for the mass number) on the left.
b. Give the period and the group of the periodic table in which you would expect to find ununhexium, explaining how you arrived at your conclusions. Further name one other chemical element that you would expect ununhexium to resemble closely.
Now that your have found the periodic table on the web, it will be easy to name the period (that's the row down from the top and it should be in the neighborhood of six or seven) and the group (that's the column number and it is in column VIA or 16 depending upon the system your prof is using. Elements in the same group have similar chemical properties; just pick one, usually the closest element to Uuh will be more similar than those further away.
c. Give the Emperical formulae of the highest hydride and highest fluoride of ununhexium explaining how you arrived at your conclusion.
One of the reasons we work on the periodic table so much is that it is so helpful at predicting properties. Think of some of the hydrogen compounds of this group (H2O and H2S, for example). Uuh should have similar formula with hydrogen. For the fluoride, act similarly. Think what compounds you find for S and F or Se and F. Explaining how you arrived at these answers should be simple enough; i.e., you are using other elements to predict the formulae for Uuh.
d. Suppose that the isotope of ununhexium undergoes a succession of seven alpha - decay reactions.
The nucleus of an atom may disintegrate by a process we call radioactivity. Alpha and beta particles as well as gamma rays are often emitted in the process. An alpha particle is nothing more than a He nucleus and those have an atomic number of 2 and a mass number of 4. In this process, mass and protons are conserved which simply means that the number of protons must add up on both sides and the mass number must do the same. So we write the equation, assuming 116Uuh292 is the element with which we start.
Uuh292 ==> 7 2He4 + zzXyy. Now all you need to do is to make the zz number + 7*2 add up to 116 and the yy number + 7*4 add up to 292. THEN look on the periodic table to see which element has an atomic number of the zz number and replace X with the symbol for that element. I hope you're with me so far.
d1. What isotope would be the final product of these changes? show how you arrived at your answer
This part is answered in the previous explanation.
d2. Is the final product a lanthanide, an actinide, a transition element or a typical element?
After you know the final product, you will know WHERE it is in the periodic table and that will tell you the answer to this part. Remember how the table is divided.
Note in part (d), that the 116 didn't print. That long equation should have started with
116Uuh292
a. The atomic number of ununhexium is 116. The full symbol for the isotope of ununhexium depends on the mass number, which is not specified in the question. You can visit the website www.webelements.com and search for element #116 to find more details and the specific mass number for the isotope.
b. To determine the period and group of ununhexium on the periodic table, you can again refer to an online periodic table. Based on the atomic number 116, you should find ununhexium in period 7 (the seventh row from the top). To determine the group, look for the column that element 116 falls into. It will likely be in group VIA or 16, depending on the periodic table system your professor uses.
For a chemical element that closely resembles ununhexium, you can look at other elements in the same group as ununhexium. These elements tend to have similar chemical properties. For example, polonium (Po) is in the same group as ununhexium and may be a close resemblance in terms of chemical properties.
c. The empirical formulas of the highest hydride and highest fluoride of ununhexium can be predicted based on the periodic trends. Elements in the same group tend to have similar chemical properties and form similar compounds. So, for the highest hydride, you can look at other Group VIA elements like polonium and sulfur, which form hydrides with the formula H2Po and H2S, respectively. By analogy, you can predict that the highest hydride of ununhexium would be H2Uuh.
Similarly, for the highest fluoride, you can look at Group VIA elements like oxygen and sulfur, which form fluorides with the formulas OF2 and SF6, respectively. Based on these analogies, you can predict that the highest fluoride of ununhexium would be F2Uuh.
d1. To determine the final product of the seven alpha-decay reactions, you need to conserve mass and atomic numbers. Each alpha particle (2 protons and 2 neutrons) results in a decrease of 4 in the mass number (mass number - 4) and 2 in the atomic number (atomic number - 2).
Starting with the isotope of ununhexium, which has an atomic number of 116, you can subtract 2 for each alpha decay. After seven alpha decays, the resulting atomic number would be 116 - (7 * 2) = 102.
To find the specific isotope, you can refer to the periodic table and find the element with atomic number 102. The final product would be the isotope of that element.
d2. The final product can be determined by looking at the position of the element with atomic number 102 on the periodic table. If the element with atomic number 102 is in the lanthanide series (period 6) or actinide series (period 7), then the final product would be a lanthanide or actinide element, respectively. If the element is in the transition metals section, it would be a transition element. If it is in one of the main groups (periods 1-6), it would be a typical element.
By using the periodic table, you can identify the element with atomic number 102 and determine its group and period to classify the final product.