Math

posted by .

I need help with this problem.

The electricity meter on Donna's house
read 71,236.4 kwh at the beginning of
March and 73,196.2 kwh at the end of
March. She pays 7.4% per kwh.
What is the amount of her electricity
bill for March? Round to the nearest cent.

Do I add the kwh's used and divide 7.4?
Please help. Not sure how to work this,
and round to the nearest cent.
















Subtract the initial from the final kwh readings to get the amount consumed for the month: 1958.8 kwh. The cost per kwh is 7.4 cents, NOT 7.4%. (That is a pretty low rate nowadays). The product of the amount consumed and the rate is $145.03 (after converting cents to dollars and rounding to the nearest cent)

which tool should be used to measure the mass of a bag of apples?
thermometer
inch ruler
produce scale
measuring cup

Take a wild guess. This is not a hard question.

thermometer duh

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Math Please check

    The electricity meter on Donna's house read 71,236.4 kwh at the beginning of March and 73,196.2 kwh at the end of March. She pays 7.4 per kwh. What is the amount of her electricity bill for March?
  2. physics

    How many kWh of energy would be needed for brushing your teeth with an electric toothbrush daiy for the month of May?
  3. phyical science

    A microwave oven has a power requirement of 1235 W. A frozen dinner requires 6.0 min to heat on full power. (a) How much electrical energy (in kWh) is used?
  4. consumer math

    If you used 648 KWH and the power company charges 0.05954/KWH with a customer charge of $2.85, how much will you pay?
  5. Math

    The amount of a monthly electric bill (B, measured in $) depends on the amount of electricity used that month (E, measured in kWh). A typical public utility charges $0.12 per kWh for the first 300 kWh used, $0.17 per kWh for the next …
  6. GCSE Physics

    The energy value of gas used in a home is measured in KWH. The home owner has a prepayment meter and pays £30 into his account. With a prepayment meter, gas cost 15p per KWH. Use the below equation to calculate the total number of …
  7. math

    In a normal month you use 1200 kWh of electricity. Your electricity provider has decided to increase the rate it charges for electricity by $0.05 per kWh. If you continue to use electricity at the same rate, how much more will it cost …
  8. Math

    The “Limited Plan” offers a 15% discount for power usage between 7pm – 9am if most of your usage happens during that time. If not, then you lose your discount and you pay a 20% premium on the usage outside of that time. The cost …
  9. Algebra 1- Please help whenever you get the chance

    The monthly cost of electricity in Smithville is determined by the function C(e) = $0.16e + $24.54, where e is the amount of electricity used in kilowatt-hours (kWh) and C(e) is the total cost. If the Fox family used 872 kWh of electricity …
  10. math answer check

    14. Knowing that you use 245 KWH 7 a.m. – 7 p.m. and 165 KWH 7 p.m. – 7 a.m., answer the following questions using the chart below: Constant Usage $0.05324/KWH Daytimer (Most usage between 7 a.m. – 7 p.m.) As long as most power …

More Similar Questions