Let f be the frequency, v wav the speed, and T the period of a sinusoidal traveling wave. The correct relationship is:
a)f=1/T
b)f=vwav + T
c)f=vwavT
d)f=vwav/T
e)f=T/vwav
My thoughts:
I think the answer is D.Since frequency is equal to T=1/f so f=1/T. Vwav is connected to f by the equation v=lambda* frequency. so together you
so I figured that it would come out to be f=vwav/T
For a transverse wave on a string the strong displacement is described as y(x,t)=f(x-at), where f is a given function and a is a positive constant. Which of the following does not necessarily follow this statement?
a)the shape of the string at time t=o is given by f(x)
b) the shape of the waveform does not change as it moves along a string
c) the waveform moves in the positive x direction
d) the speed of the waveform is a
e) the speed of the waveform is x/t
thoughts:
I think the statement that does not necessarily apply is d. The a in the equation is not refering to the wave speed but to the angular frequency or w based on the equation.
y=Ysin(kx-wt)
Thank you for your help.
<<Since frequency is equal to T=1/f so f=1/T. Vwav is connected to f by the equation v=lambda* frequency. so together you
so I figured that it would come out to be f=vwav/T
>>
How can you have both f = 1/T and f = Vwav/T ? The second equation is dimensionally inconsistent.
Your second answer is also wrong. The question has nothing to do with angular velocity.
Let's go through the first question again to clarify the relationship between frequency, wave speed, and period.
The correct relationship is given by f = 1/T, where f is the frequency and T is the period of the wave. This means that the frequency is the reciprocal of the period.
To understand this relationship, let's break it down step by step:
1. Frequency (f): The frequency of a wave is the number of cycles or oscillations that occur per unit time. It is measured in hertz (Hz), which is equal to one cycle per second.
2. Period (T): The period of a wave is the time it takes for one complete cycle or oscillation. It is measured in seconds (s).
The relationship between frequency and period is inverse: as the period increases, the frequency decreases, and vice versa.
Now, let's consider the equation v = λ * f, where v is the wave speed and λ (lambda) is the wavelength.
3. Wave speed (v): The wave speed is the speed at which a wave propagates through a medium. It is determined by the properties of the medium and is measured in meters per second (m/s).
4. Wavelength (λ): The wavelength is the distance between two consecutive points on a wave that are in phase (e.g., peak to peak or trough to trough). It is measured in meters (m).
The equation v = λ * f relates the wave speed, wavelength, and frequency. It states that the wave speed is equal to the product of the wavelength and the frequency.
Now, if we rearrange the equation v = λ * f to solve for f, we get f = v/λ. This equation tells us that the frequency is equal to the wave speed divided by the wavelength.
To summarize:
- The correct relationship between frequency, wave speed, and period is f = 1/T.
- The equation f = v/λ relates the frequency, wave speed, and wavelength.
Therefore, the correct answer to the first question is (a) f = 1/T.