I couldn't find the sets of factors that add up to -13 in this problem. I have to solve this problem by factoring, not anything like the -b/2a or anything. Plz help, anything is greatly appreciated!
x^2-13x+36
Thx for helping ppl!
Emily,
Couldnt it be anything like 2x+-15x?
or like
x-6.5x+18
You have to find the factors of 1 (coefficient of x^2) and 36 (the constant) that multiply together then add together and make -13. It would work if it were -12 instead, but it's -13. I don't have the answers to this problem, it's off a worksheet so it isn't off of any website. Thx for trying to help me out anyway, Shaydie! U R awesome.
(((((@----->-----)))))
(x - 4)*(x-9)
Thanks!!!
I got confused while I was figuring out the problem. I wrote it right, but I was trying to figure out what factors of 13 and 36 added up to -13, instead of 1 and 36. I feel so stupid! Anyway, thx for helping, Count Iblis! Happy Valentine's Day
No problem, I'm here to help! Let's walk through the factoring process to find the correct sets of factors for the quadratic equation x^2 - 13x + 36.
To factor this quadratic equation, we need to find two numbers that multiply to give us the product of the coefficient of x^2 (which is 1) and the constant term (which is 36), and at the same time, add up to the coefficient of x (which is -13).
First, let's write down all the pairs of factors of 1 and 36:
Factors of 1: 1, -1
Factors of 36: 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 9, -9, 12, -12, 18, -18, 36, -36
Now, we need to check which pairs of factors add up to -13. Let's go through them one by one:
(1, 36) -> 1 + 36 = 37
(-1, -36) -> -1 + (-36) = -37
(1, -36) -> 1 + (-36) = -35
(-1, 36) -> -1 + 36 = 35
(2, 18) -> 2 + 18 = 20
(-2, -18) -> -2 + (-18) = -20
(2, -18) -> 2 + (-18) = -16
(-2, 18) -> -2 + 18 = 16
(3, 12) -> 3 + 12 = 15
(-3, -12) -> -3 + (-12) = -15
(3, -12) -> 3 + (-12) = -9
(-3, 12) -> -3 + 12 = 9
(4, 9) -> 4 + 9 = 13
(-4, -9) -> -4 + (-9) = -13
(4, -9) -> 4 + (-9) = -5
(-4, 9) -> -4 + 9 = 5
(6, 6) -> 6 + 6 = 12
(-6, -6) -> -6 + (-6) = -12
(6, -6) -> 6 + (-6) = 0
(-6, 6) -> -6 + 6 = 0
As we can see, the only pair that adds up to -13 is (-4, -9).
Therefore, the correct factored form of the quadratic equation x^2 - 13x + 36 is:
(x - 4)(x - 9)
I hope this clears up any confusion! Let me know if you have any further questions.