A bicyclist travels in a circle of radius 35.0 m at a constant speed of 7.00 m/s. The bicycle-rider mass is 72.0 kg.
Calculate the magnitude of the force of friction on the bicycle from the road.
Calculate the magnitude of the net force on the bicycle from the road.
I figured this one out too but I still can't get the other one about the string :/
To calculate the magnitude of the force of friction on the bicycle from the road, we can use the centripetal force formula. The centripetal force is provided by the friction between the bike's tires and the road. It is given by the equation:
Fc = mv²/r
Where:
Fc is the centripetal force
m is the mass of the bicycle-rider system
v is the velocity of the bicycle
r is the radius of the circular path
Substituting the given values into the equation, we get:
Fc = (72.0 kg)(7.00 m/s)²/(35.0 m)
= 88.8 N
Therefore, the magnitude of the force of friction on the bicycle from the road is 88.8 N.
To calculate the magnitude of the net force on the bicycle from the road, we need to consider all the forces acting on the bicycle. In this case, the only force acting on the bicycle is the force of friction, since there is no mention of any other external forces. Thus, the magnitude of the net force on the bicycle is equal to the magnitude of the force of friction:
Net force = 88.8 N
So, the magnitude of the net force on the bicycle from the road is also 88.8 N.
If you have a question about a string, please provide me with more details or specify the context so I can help you with it.