Intravenous medications are often administered in 7% glucose (C6H12O6). what is the osmotic pressure of such solutions at 44 degrees C (body temperture)? the density of the solution is 1 g/mol.
I would convert the percent concentration to Molarity.
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To calculate the osmotic pressure of a solution, we need to convert the percent concentration to molarity.
The given solution is 7% glucose (C6H12O6). To convert this to molarity, we need to know the molar mass of glucose. The molar mass of glucose (C6H12O6) is calculated as follows:
(6 atoms of carbon * atomic mass of carbon) + (12 atoms of hydrogen * atomic mass of hydrogen) + (6 atoms of oxygen * atomic mass of oxygen) = 6*12 + 12*1 + 6*16 = 72 + 12 + 96 = 180 g/mol
Now, we can convert the 7% glucose solution to molarity. The percent concentration indicates that there are 7 grams of glucose in 100 grams of solution.
First, let's calculate the moles of glucose in the solution:
Moles of glucose = mass of glucose / molar mass of glucose
Moles of glucose = 7g / 180 g/mol
Moles of glucose = 0.0389 mol
Next, we need to calculate the volume of the solution from the given density. We are given that the density of the solution is 1 g/mL. Since the molar mass of glucose is equal to the density in grams per liter (1g/mol), we can conclude that the solution has a volume of 1L.
Now we can calculate the molarity:
Molarity (M) = moles of solute / volume of solution in liters
Molarity (M) = 0.0389 mol / 1 L
Molarity (M) = 0.0389 M
Now, let's move on to calculating the osmotic pressure. The osmotic pressure (π) can be calculated using the following formula:
π = nRT
where:
π - osmotic pressure in units of pressure (e.g., pascals or atmospheres)
n - molar concentration
R - ideal gas constant (0.0821 L.atm/mol.K)
T - temperature in Kelvin
The temperature given is 44 degrees Celsius, which needs to be converted to Kelvin:
Temperature in Kelvin = 44 + 273.15
Temperature in Kelvin = 317.15 K
Now we can calculate the osmotic pressure using the formula:
π = (0.0389 mol/L) * (0.0821 L.atm/mol.K) * (317.15 K)
π ≈ 1.018 atm
Therefore, the osmotic pressure of the 7% glucose solution at 44 degrees Celsius is approximately 1.018 atm.