A 17 N horizontal force F pushes a block weighing 6.0 N against a vertical wall. The coefficient of static friction between the wall and the block is 0.68, and the coefficient of kinetic friction is 0.48. Assume that the block is not moving initially. Will the block move? In unit-vector notation, what is the force exerted on the block by the wall?

Force friction= mu*17= 11.6N
weight= 6N. Force of friction prevents it from moving.

To determine whether or not the block will move, we need to compare the force of friction with the force applied.

The force of friction is given by the equation:

Force friction = coefficient of static friction * normal force

where the normal force is equal to the weight of the block (since the block is pressed against the vertical wall).

In this case, the coefficient of static friction is 0.68 and the weight of the block is 6.0 N. Therefore, the force of friction is:

Force friction = 0.68 * 6.0 N = 4.08 N

The force applied is given as a 17 N horizontal force.

To determine if the block will move, we compare the force applied (17 N) with the force of friction (4.08 N). If the force applied is greater than the force of friction, the block will move; if not, the block will remain stationary.

In this case, the force applied (17 N) is greater than the force of friction (4.08 N), so the block will move.

To find the force exerted on the block by the wall in unit-vector notation, note that the force exerted by the wall acts in the opposite direction to the force applied. Therefore, the force exerted by the wall is equal in magnitude but opposite in direction to the applied force.

Using unit-vector notation, we can express this force as:

Force exerted by the wall = (-17 N)i

where "i" is the unit vector in the horizontal direction.