posted by mukesh .
The perimeter of a rectangle is 68 f. Find the dimensions of the rectangle if the ratioof the length to the width is 9:8
I am sorry that nobody has responded earlier.
The perimeter is the sum of the length of the four sides. Therefore:
2(9X) + 2(8X) = 68
Solve for X. Then 9X and 8X will give you the dimensions.
I hope this helps. Thanks for asking.