I need help on this
12(p+3)>2+ 13(p+3)+3
multiply out the parenthesis
subtract 12 p from both sides.
Add to both sides 2+39 +3.
To solve the given inequality, 12(p+3) > 2 + 13(p+3) + 3, you should first simplify both sides of the inequality.
Step 1: Multiply out the parentheses:
12(p+3) becomes 12p + 36, and
2 + 13(p+3) + 3 becomes 2 + 13p + 39 + 3.
Simplifying further, we have:
12p + 36 > 2 + 13p + 39 + 3.
Step 2: Combine like terms on both sides:
12p + 36 > 13p + 44.
Step 3: Now, to isolate the variable "p", we need to subtract 12p from both sides to get rid of the 12p term. This will give us:
12p - 12p + 36 > 13p - 12p + 44.
Simplifying further, the inequality becomes:
36 > p + 44.
Step 4: Subtract 44 from both sides to isolate the "p" term on one side:
36 - 44 > p + 44 - 44.
Simplifying, we get:
-8 > p.
So, the solution to the inequality is p < -8.
Remember to double-check your work and ensure that the inequality sign is correct in each step of the solution process.