Quadratic Equations

posted by .

Ok, I am supposed to find out what the variables are by factoring and finding square roots. I couldn't find the right factors of a and c that added up to b in the equation (did that make sense?). Please help me find them! TYVM

-5n+6n^2-4=0

I know bobpursley helped me with this problem not too long ago, but he asked if it was 6n^2-5n-4, but it isn't. The help with the other problem was great! Plz help, any help is greatly appreciated!

Think. it is what I typed. Rearranging the terms does not change the polynomial. Relook at the solution I presented.



omg how could I be SOOOOOOOOO stupid!!?? I didn't think about rearranging the terms. I can be such an idiot sometimes. Thanks for bearing with my stupidness!!

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math

    Still looking at how to solve these... Both are cubic polynomials?
  2. Quadratic Equations

    Ok, I am supposed to find out what the variables are by factoring and finding square roots. I couldn't find the right factors of a and c that added up to b in the equation (did that make sense?
  3. Quadratic Equations

    I couldn't find the sets of factors that add up to -13 in this problem. I have to solve this problem by factoring, not anything like the -b/2a or anything. Plz help, anything is greatly appreciated! x^2-13x+36 Thx for helping ppl! …
  4. Algebra2

    Find the polynomials roots to each of the following problems: #1) x^2+3x+1 #2) x^2+4x+3=0 #3) -2x^2+4x-5 #3 is not an equation. Dod you omit "= 0" at the end?
  5. algebra

    1)Solve by factoring:5x^2=4-19x answer=-4,1/5 2)Which quadratic equation has roots 7 and -2/3?
  6. Alg II

    I'm working with finding roots of polynomial equations with degrees of 3 or higher. I have the equation r(x)=x^4-6x^3+12x^2=6x-13 I used a graphing calculator to find the real roots of 1,-1 Then I did synthetic using -1, and I ended …
  7. Alg II

    I'm working with finding roots of polynomial equations with degrees of 3 or higher. I have the equation r(x)=x^4-6x^3+12x^2=6x-13 I used a graphing calculator to find the real roots of 1,-1 Then I did synthetic using -1, and I ended …
  8. Math

    Solve the equation by factoring, by finding square roots, or by using the quadratic formula. 3(x+4)^2= -27
  9. Math

    2x(x+3) = 0 Is there a way to solve that using the below methods?
  10. Math

    I can't remember how you find the roots of quadratic equations other than determining the zeroes of the equation and finding the x-intercepts. Can someone please give me a clear answer on this as my dad has been useless on this topic …

More Similar Questions