physics
posted by **chocolatekisses .
A 35kg skier skis directly down a frictionless slope angled at 11° to the horizontal. Assume the skier moves in the negative direction of an x axis along the slope. A wind force with component Fx acts on the skier. What is Fx (in N) if the magnitude of the skier's velocity is.. constant? ..increasing at a rate of 1.0 m/s^2? ..increasing at a rate of 2.0 m/s^2?
Writing the sum of the forces down the slope....
Weight*sinThetaWindfriction=mass*acceleration.
In the first part, a=0
so..
35*sin(11)Fx=0
and solvee for Fx?
.. as for the increasing rate.. is it telling me that the 1.0m/s2 is added to the gravity of 9.8m/s2?

physics 
JT
this is kinda late answer, but still...
35*sin(11)Fx=0
This works for a = 0
35*sin(11)+maFx=0
More complete answer... (a!=0)
So, for increasing rate of a = 1m/s^2
This is going in negative direction, so
35*sin(11)+(35)(1)=Fx
And for a = 22/s^2
35*sin(11)+(35)(2)=Fx
Crunch in calculator for Fx in Newtons 
physics 
JT
Actually, just noticed that was for in x direction, so change sign on acceleration
35*sin(11)+(35)(1)=Fx
35*sin(11)+(35)(2)=Fx 
physics 
stuff
ur supposed to multiply the 35sintheta with the acceleration due to gravity (9.8)
Respond to this Question
Similar Questions

physics
A 40 kg skier comes directly down a frictionless ski slope that is inclined at an angle of 10 degrees with the horizontal while a strong wind blows parallel to the slope. Determine the magnitude and diercection of the force of the … 
physics
A 40 kg skier comes directly down a frictionless ski slope that is inclined at an angle of 10 degrees with the horizontal while a strong wind blows parallel to the slope. Determine the magnitude and diercection of the force of the … 
college level physics
a 40 kg skier skis down a frictionless slope angled at 10 degrees to the horizontal. Assume the skier moves in the negative direction of an x axis along the slope. A wind force with component Fx acts on the skier. What is Fx is the … 
physics
A skier with a mass of 70 kg starts from rest and skis down an icy (frictionless) slope that has a length of 52 m at an angle of 32° with respect to the horizontal. At the bottom of the slope, the path levels out and becomes horizontal, … 
physics
A 48 kg skier skis directly down a frictionless slope angled at 5° to the horizontal. Assume the skier moves in the negative direction of an x axis along the slope. A wind force with component Fx acts on the skier. (a) What is Fx … 
Physics
A skier with a mass of 56 kg starts from rest and skis down an icy (frictionless) slope that has a length of 70 m at an angle of 32° with respect to the horizontal. At the bottom of the slope, the path levels out and becomes horizontal, … 
Physics
A skier with a mass of 66.6 kg starts from rest and skis down an icy (frictionless) slope that has a length of 58.4 m at an angle of 29.8° with respect to the horizontal. At the bottom of the slope, the path levels out and becomes … 
Physics
A skier is pulled up a slope at a constant velocity by a tow bar. The slope is inclined at 23.0° with respect to the horizontal. The force applied to the skier by the tow bar is parallel to the slope. The skier's mass is 55.3 kg, … 
science
A skier with a mass of 60.0 kg starts from rest and skis down an icy (frictionless) slope that has a length of 53.0 m at an angle of 25.4° with respect to the horizontal. At the bottom of the slope, the path levels out and becomes … 
Physics
A 64 kg skier is on a 18 degree slope. The coefficient of kinetic friction between the skis and snow is .04. A) What is the weight of the skier?