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Write the balanced equation, with the enthalpy component, for the rusting process, given that Hf for iron and oxygen is 0 and Hf for ferric oxide is -826 kJ/mol.

4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s)




You need to add the heat one of three ways.
4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s) + heat or

4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s) delta H = -826 kJ/mol or

4 Fe (s) + 3 O2 (g) --------> 2 Fe2O3 (s) delta H = -3304 kJ

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