Is C7h16 + O2 = 7 CO2 + 8 H2O a balance chemical equation?

C balances. H balances (you should capitalize it). O is not balanced. You need a coefficient of 11 for O2. Check that.

C7H16+O2=7CO2+2H2O

Chemistry

To balance the equation C7H16 + O2 = 7CO2 + 8H2O, let's start by counting the atoms on each side of the equation.

On the left side:
C: 7
H: 16
O: 2

On the right side:
C: 7
H: 8
O: 18

As you correctly pointed out, the number of oxygen atoms is not balanced. To balance the equation, we need 11 molecules of O2 on the left side.

The balanced equation is:
C7H16 + 11O2 = 7CO2 + 8H2O

Now, the equation is balanced for both carbon and oxygen.

To determine if the chemical equation "C7H16 + O2 = 7 CO2 + 8 H2O" is balanced, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by counting the atoms of each element. On the left side, we have:

- Carbon (C): 7 atoms
- Hydrogen (H): 16 atoms
- Oxygen (O): 2 atoms (since there is only one molecule of O2)

On the right side, we have:

- Carbon (C): 7 atoms
- Hydrogen (H): 16 atoms (H2O has 2 hydrogen atoms per molecule, so we multiply by the coefficient of 8)
- Oxygen (O): 21 atoms (CO2 has 2 oxygen atoms per molecule, so we multiply by the coefficient of 7, and H2O has 1 oxygen atom per molecule, so we multiply by the coefficient of 8)

Since the number of carbon and hydrogen atoms is the same on both sides, we only need to balance the oxygen atoms.

To balance the oxygen atoms, we need to have the same number of oxygen atoms on both sides of the equation. To do this, we can adjust the coefficient in front of O2. In this case, we need a coefficient of 11 in front of O2 to balance the oxygen atoms.

Therefore, the balanced chemical equation is:

C7H16 + 11 O2 = 7 CO2 + 8 H2O