chemistry
posted by Rob .
If, for a secondorder reaction, the elapsed time after the first halflife is 338.871 seconds, the elapsed time after four halflives would be (in minutes)...
t_{1/2}= 1/k(A).
k= 1/t_{1/2}*(A)=1/338.871 s(1)
(I let (A)=1).
k = ??
After 4 half lives, beginning of the 5th, (A) = 1/2^{4} = 1/16 of the original.
then t_{1/2}=[1/k(1/16)] =
16*1/k=16*338.871 = ??
Change to minutes.
Check my thinking.
So t_{1/2} =
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